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Math Puzzle

Posted by | Sep 22, 2020 | | 0

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The formula

(x-5)(x-4)(x-3)(x-2)(x-1)x(x+1)(x+2)(x+3)(x+4)(x+5)

could of course be expanded out into a polynomial. As you might gather, it would be a polynomial of order 11, with 12 coefficients, i.e., ax11+bx10…+ix2+jx+k. So far, nothing mysterious here.

What is the value of the sum of all the coefficients, a+b+…+i+j+k? Show all work!

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Eugene Volokh

Founded in 1968, Reason is the magazine of free minds and free markets. We produce hard-hitting independent journalism on civil liberties, politics, technology, culture, policy, and commerce. Reason exists outside of the left/right echo chamber. Our goal is to deliver fresh, unbiased information and insights to our readers, viewers, and listeners every day. Visit https://reason.com

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