Math Puzzle
The formula
(x-5)(x-4)(x-3)(x-2)(x-1)x(x+1)(x+2)(x+3)(x+4)(x+5)
could of course be expanded out into a polynomial. As you might gather, it would be a polynomial of order 11, with 12 coefficients, i.e., ax11+bx10…+ix2+jx+k. So far, nothing mysterious here.
What is the value of the sum of all the coefficients, a+b+…+i+j+k? Show all work!
This post has been republished with permission from a publicly-available RSS feed found on Reason. The views expressed by the original author(s) do not necessarily reflect the opinions or views of The Libertarian Hub, its owners or administrators. Any images included in the original article belong to and are the sole responsibility of the original author/website. The Libertarian Hub makes no claims of ownership of any imported photos/images and shall not be held liable for any unintended copyright infringement. Submit a DCMA takedown request.